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I must note: if a drop is .1%, and you do X to roll of the chance of obtaining the drop 1000 times, you are not guaranteed the drop.  
I must note: if a drop is .1%, and you do X to roll of the chance of obtaining the drop 1000 times, you are not guaranteed the drop.  
(Just like if you flip a coin 10 times, you may only get heads twice, even though it's a 50% chance you get heads!)
(Just like if you flip a coin 10 times, you may only get heads twice, even though it's a 50% chance you get heads!)



Revision as of 01:51, 28 August 2024

Yeah unfortunately your math is wrong. The way statics works doesn't follow your thought process.

If the chance of obtaining a Gold Coin Chest is .1%, and you can hit a pile 3-10 times, each time you hit the pile, the probability of getting a Gold Coin Chest remains at .1%.

However, with ten chances, overall, the odds go up to 0.996% in comparison to if someone only hit the pile once.

In layman's terms, every time you hit the pile, you're only going to get a chest .1% of the time. But the more you hit the pile, the more likely it is that you get a chest.

I must note: if a drop is .1%, and you do X to roll of the chance of obtaining the drop 1000 times, you are not guaranteed the drop.

(Just like if you flip a coin 10 times, you may only get heads twice, even though it's a 50% chance you get heads!)

Binomial distribution: Variance=n⋅p⋅(1−p)

n is the number of pulls from the pile, which is 10.

p is the probability of getting a chest per pull, which is 0.1.

So, the variance of the number of chests obtained from 10 pulls is 0.9.