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Binomial distribution: | Binomial distribution: | ||
Variance=n⋅p⋅(1−p) | Variance=n⋅p⋅(1−p) | ||
n is the number of pulls from the pile, which is 10. | n is the number of pulls from the pile, which is 10. | ||
p is the probability of getting a chest per pull, which is 0.1. | p is the probability of getting a chest per pull, which is 0.1. | ||
So, the variance of the number of chests obtained from 10 pulls is 0.9. | So, the variance of the number of chests obtained from 10 pulls is 0.9. |
Revision as of 01:48, 28 August 2024
Yeah unfortunately your math is wrong. The way statics works doesn't follow your thought process.
If the chance of obtaining a Gold Coin Chest is .1%, and you can hit a pile 3-10 times, each time you hit the pile, the probability of getting a Gold Coin Chest remains at .1%.
However, with ten chances, overall, the odds go up to 0.996% in comparison to if someone only hit the pile once.
In layman's terms, every time you hit the pile, you're only going to get a chest .1% of the time. But the more you hit the pile, the more likely it is that you get a chest.
I must note: if a drop is .1%, and you do X to roll of the chance of obtaining the drop 1000 times, you are not guaranteed the drop.
Binomial distribution: Variance=n⋅p⋅(1−p)
n is the number of pulls from the pile, which is 10.
p is the probability of getting a chest per pull, which is 0.1.
So, the variance of the number of chests obtained from 10 pulls is 0.9.