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If the chance of obtaining a Gold Coin Chest is .1%, and you can hit a pile 3-10 times, each time you hit the pile, the probability of getting a Gold Coin Chest remains at .1%.
If the chance of obtaining a Gold Coin Chest is .1%, and you can hit a pile 3-10 times, each time you hit the pile, the probability of getting a Gold Coin Chest remains at .1%.


However, with ten chances, overall, the odds go up to 0.996% in comparison to if someone only hit the pile once.
[[However, with ten chances, overall, the odds go up to 0.996% in comparison to if someone only hit the pile once.]]
 


In layman's terms, every time you hit the pile, you're only going to get a chest .1% of the time. But the more you hit the pile, the more likely it is that you get a chest.
In layman's terms, every time you hit the pile, you're only going to get a chest .1% of the time. But the more you hit the pile, the more likely it is that you get a chest.


I must note: if a drop is .1%, and you do X to roll of the chance of obtaining the drop 1000 times, you are not guaranteed the drop.
I must note: if a drop is .1%, and you do X to roll of the chance of obtaining the drop 1000 times, you are not guaranteed the drop.  
 
(Just like if you flip a coin 10 times, you may only get heads twice, even though it's a 50% chance you get heads!)
 
[[This is called relative frequency, which in this case, is 20%]]
 
[[If you flipped a coin 1000 times, you would get heads close to 500 times, but it's not guaranteed.]]
 


Binomial distribution:  
[[Binomial distribution:]]
Variance=n⋅p⋅(1−p)
[[Variance=n⋅p⋅(1−p)]]


n is the number of pulls from the pile, which is 10.
[[n is the number of pulls from the pile, which is 10.]]


p is the probability of getting a chest per pull, which is 0.1.
[[p is the probability of getting a chest per pull, which is 0.1.]]


So, the variance of the number of chests obtained from 10 pulls is 0.9.
[[So, the variance of the number of chests obtained from 10 pulls is 0.9.]]

Latest revision as of 01:59, 28 August 2024

Yeah unfortunately your math is wrong. The way statics works doesn't follow your thought process.

If the chance of obtaining a Gold Coin Chest is .1%, and you can hit a pile 3-10 times, each time you hit the pile, the probability of getting a Gold Coin Chest remains at .1%.

However, with ten chances, overall, the odds go up to 0.996% in comparison to if someone only hit the pile once.


In layman's terms, every time you hit the pile, you're only going to get a chest .1% of the time. But the more you hit the pile, the more likely it is that you get a chest.

I must note: if a drop is .1%, and you do X to roll of the chance of obtaining the drop 1000 times, you are not guaranteed the drop.

(Just like if you flip a coin 10 times, you may only get heads twice, even though it's a 50% chance you get heads!)

This is called relative frequency, which in this case, is 20%

If you flipped a coin 1000 times, you would get heads close to 500 times, but it's not guaranteed.


Binomial distribution: Variance=n⋅p⋅(1−p)

n is the number of pulls from the pile, which is 10.

p is the probability of getting a chest per pull, which is 0.1.

So, the variance of the number of chests obtained from 10 pulls is 0.9.